Re: OMFG! SE is nerfing NIN and RNG!!!
I think you don't understand what acceleration is. Acceleration is the rate of change in velocity. To have acceleration, you must obey Newton's law of equal and opposite reactions. This law is obeyed while the bullet travels down the barrel of the gun and a bullet is being pushed by the string of the bow. One force is pushing on the gun/bow and the other on the bullet/arrow, equal and opposite forces. Because the mass of the bullet/arrow is so much less than the gun/bow, more force is transfered to the velocity in the equation.
I never implied it was instaneous. The acceleration occurs only while the bullet is traveling through the barrel (expanding gas pressure) and the bow string is pushing the arrow. This takes time (very little), but all the horizontal acceleration occurs in this period. Once it leaves the barrel/bow string there is no outside force acting on it that could cause further acceleration (you would need equal and opposite force for more acceleration to occur, what is being pushed as a reaction of the bullet accelerating later?). You mention gravity, but that has no effect on horizontal acceleration as I explained in my previous post. Only air resistance slows the horizontal velocity, and that is a very minor factor and insignifigant at the ranges encountered in game. If we were discussing rockets, you physics would be correct in that they continue to accelerate after launch, but bullets and arrows travel solely on inertia after launch and expereince no further acceleration.
Here is an excerpt from that report I linked in my earlier post which you didn't read:
Here is a very good physics discussion of bullet momentum and acceleration that should clear things up.
Force = M(mass)*A(acceleration)
shooting off with a push of 100 m/s^2 and friction is taking it down 10 m/s^2 thus
(1s = 90 m/s^2), (2s = 80m/s^2), (3s = 70m/s^2), etc.
Until 10 seconds later where acceleration = 0, now is going at constant speed = peak theoretical damage.
By definition of acceleration, there is time involved, that means going from 100 -> zero is not possible without the passing of time.
(1s = 90 m/s^2), (2s = 80m/s^2), (3s = 70m/s^2), etc.
Until 10 seconds later where acceleration = 0, now is going at constant speed = peak theoretical damage.
By definition of acceleration, there is time involved, that means going from 100 -> zero is not possible without the passing of time.
Here is an excerpt from that report I linked in my earlier post which you didn't read:
When one object exerts a force on a second object for a certain amount of time, the second object exerts an equal but oppositely directed force on the first object for exactly the same amount of time. The momentum lost by the first object is exactly equal to the momentum gained by the second object. Momentum is transferred from the first object to the second object. In this case, if a gun exerts a force on a bullet when firing it forward then the bullet will exert an equal force in the opposite direction on the gun causing it to move backwards or recoil. Although the action and reaction forces are equal in size the effect on the gun and the bullet are not the same since the mass of the gun is far greater than the mass of the bullet. The acceleration of the bullet while moving along the gun barrel would be much greater than the acceleration of the gun(acceleration = force mass).
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